[Leetcode] Daily Leads and Partners
정답
SELECT
date_id, make_name,
COUNT(DISTINCT lead_id) unique_leads,
COUNT(DISTINCT partner_id) unique_partners
FROM DailySales
GROUP BY date_id, make_name
✅ Point
COUNT(lead_id)
만으론 distinct 한 id의 개수를 구할 수 없음COUNT(DISTINCT lead_id)
로